1/5r^2-2=-3/10r

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Solution for 1/5r^2-2=-3/10r equation: 


r in (-oo:+oo)

(1/5)*r^2-2 = (-3/10)*r // - (-3/10)*r

(1/5)*r^2-((-3/10)*r)-2 = 0

(1/5)*r^2+(3/10)*r-2 = 0

1/5*r^2+3/10*r-2 = 0

DELTA = (3/10)^2-(-2*1/5*4)

DELTA = 169/100

DELTA > 0

r = ((169/100)^(1/2)-3/10)/(1/5*2) or r = (-(169/100)^(1/2)-3/10)/(1/5*2)

r = 5/2 or r = -4

r in { -4, 5/2 }

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